Optimal. Leaf size=163 \[ -\frac{2 a^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{c^{3/2}}-\frac{b^{3/2} (3 b c-5 a d) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{d^{5/2}}+\frac{b \sqrt{a+b x} \sqrt{c+d x} (3 b c-2 a d)}{c d^2}-\frac{2 (a+b x)^{3/2} (b c-a d)}{c d \sqrt{c+d x}} \]
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Rubi [A] time = 0.138804, antiderivative size = 163, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.364, Rules used = {98, 154, 157, 63, 217, 206, 93, 208} \[ -\frac{2 a^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{c^{3/2}}-\frac{b^{3/2} (3 b c-5 a d) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{d^{5/2}}+\frac{b \sqrt{a+b x} \sqrt{c+d x} (3 b c-2 a d)}{c d^2}-\frac{2 (a+b x)^{3/2} (b c-a d)}{c d \sqrt{c+d x}} \]
Antiderivative was successfully verified.
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Rule 98
Rule 154
Rule 157
Rule 63
Rule 217
Rule 206
Rule 93
Rule 208
Rubi steps
\begin{align*} \int \frac{(a+b x)^{5/2}}{x (c+d x)^{3/2}} \, dx &=-\frac{2 (b c-a d) (a+b x)^{3/2}}{c d \sqrt{c+d x}}+\frac{2 \int \frac{\sqrt{a+b x} \left (\frac{a^2 d}{2}+\frac{1}{2} b (3 b c-2 a d) x\right )}{x \sqrt{c+d x}} \, dx}{c d}\\ &=-\frac{2 (b c-a d) (a+b x)^{3/2}}{c d \sqrt{c+d x}}+\frac{b (3 b c-2 a d) \sqrt{a+b x} \sqrt{c+d x}}{c d^2}+\frac{2 \int \frac{\frac{a^3 d^2}{2}-\frac{1}{4} b^2 c (3 b c-5 a d) x}{x \sqrt{a+b x} \sqrt{c+d x}} \, dx}{c d^2}\\ &=-\frac{2 (b c-a d) (a+b x)^{3/2}}{c d \sqrt{c+d x}}+\frac{b (3 b c-2 a d) \sqrt{a+b x} \sqrt{c+d x}}{c d^2}+\frac{a^3 \int \frac{1}{x \sqrt{a+b x} \sqrt{c+d x}} \, dx}{c}-\frac{\left (b^2 (3 b c-5 a d)\right ) \int \frac{1}{\sqrt{a+b x} \sqrt{c+d x}} \, dx}{2 d^2}\\ &=-\frac{2 (b c-a d) (a+b x)^{3/2}}{c d \sqrt{c+d x}}+\frac{b (3 b c-2 a d) \sqrt{a+b x} \sqrt{c+d x}}{c d^2}+\frac{\left (2 a^3\right ) \operatorname{Subst}\left (\int \frac{1}{-a+c x^2} \, dx,x,\frac{\sqrt{a+b x}}{\sqrt{c+d x}}\right )}{c}-\frac{(b (3 b c-5 a d)) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c-\frac{a d}{b}+\frac{d x^2}{b}}} \, dx,x,\sqrt{a+b x}\right )}{d^2}\\ &=-\frac{2 (b c-a d) (a+b x)^{3/2}}{c d \sqrt{c+d x}}+\frac{b (3 b c-2 a d) \sqrt{a+b x} \sqrt{c+d x}}{c d^2}-\frac{2 a^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{c^{3/2}}-\frac{(b (3 b c-5 a d)) \operatorname{Subst}\left (\int \frac{1}{1-\frac{d x^2}{b}} \, dx,x,\frac{\sqrt{a+b x}}{\sqrt{c+d x}}\right )}{d^2}\\ &=-\frac{2 (b c-a d) (a+b x)^{3/2}}{c d \sqrt{c+d x}}+\frac{b (3 b c-2 a d) \sqrt{a+b x} \sqrt{c+d x}}{c d^2}-\frac{2 a^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{c^{3/2}}-\frac{b^{3/2} (3 b c-5 a d) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{d^{5/2}}\\ \end{align*}
Mathematica [C] time = 1.59291, size = 226, normalized size = 1.39 \[ \frac{2 \left (5 a \left (-\frac{a^{3/2} \sqrt{c+d x} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )}{c^{3/2}}+\frac{b \sqrt{b c-a d} \sqrt{\frac{b (c+d x)}{b c-a d}} \sinh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b c-a d}}\right )}{d^{3/2}}+\frac{\sqrt{a+b x} (a d-b c)}{c d}\right )+\frac{(a+b x)^{5/2} \left (\frac{b (c+d x)}{b c-a d}\right )^{3/2} \, _2F_1\left (\frac{3}{2},\frac{5}{2};\frac{7}{2};\frac{d (a+b x)}{a d-b c}\right )}{c+d x}\right )}{5 \sqrt{c+d x}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.021, size = 492, normalized size = 3. \begin{align*} -{\frac{1}{2\,{d}^{2}c}\sqrt{bx+a} \left ( 2\,\ln \left ({\frac{adx+bcx+2\,\sqrt{ac}\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }+2\,ac}{x}} \right ) x{a}^{3}{d}^{3}\sqrt{bd}-5\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) xa{b}^{2}c{d}^{2}\sqrt{ac}+3\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) x{b}^{3}{c}^{2}d\sqrt{ac}+2\,\sqrt{bd}\ln \left ({\frac{adx+bcx+2\,\sqrt{ac}\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }+2\,ac}{x}} \right ){a}^{3}c{d}^{2}-5\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) \sqrt{ac}a{b}^{2}{c}^{2}d+3\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) \sqrt{ac}{b}^{3}{c}^{3}-2\,\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{bd}\sqrt{ac}x{b}^{2}cd-4\,\sqrt{bd}\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{ac}{a}^{2}{d}^{2}+8\,\sqrt{bd}\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{ac}abcd-6\,\sqrt{bd}\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }\sqrt{ac}{b}^{2}{c}^{2} \right ){\frac{1}{\sqrt{ \left ( bx+a \right ) \left ( dx+c \right ) }}}{\frac{1}{\sqrt{bd}}}{\frac{1}{\sqrt{ac}}}{\frac{1}{\sqrt{dx+c}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 16.2662, size = 2601, normalized size = 15.96 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + b x\right )^{\frac{5}{2}}}{x \left (c + d x\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.45729, size = 392, normalized size = 2.4 \begin{align*} \frac{2 \, \sqrt{b d} a^{3} b \arctan \left (\frac{b^{2} c + a b d -{\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2}}{2 \, \sqrt{-a b c d} b}\right )}{\sqrt{-a b c d} c{\left | b \right |}} - \frac{{\left (\frac{{\left (b x + a\right )} b^{5} c d^{2}}{b^{6} c d^{4} - a b^{5} d^{5}} + \frac{3 \, b^{6} c^{2} d - 5 \, a b^{5} c d^{2} + 2 \, a^{2} b^{4} d^{3}}{b^{6} c d^{4} - a b^{5} d^{5}}\right )} \sqrt{b x + a}}{32 \, \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}} - \frac{{\left (3 \, \sqrt{b d} b c^{2} - 5 \, \sqrt{b d} a c d\right )} \log \left ({\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2}\right )}{64 \,{\left (b^{2} c d^{4} - a b d^{5}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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